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A charged particle with a velocity 2×10³ ms⁻¹ passes undeflected through electric field and magnetic fields in mutually perpendicular directions. The magnetic field is 1.5T. The magnitude of electric field will be
Options
(a) 1.5×10³ NC⁻¹
(b) 2×10³ NC⁻¹
(c) 3×10³ NC⁻¹
(d) 1.33×10³ NC⁻¹
Correct Answer:
3×10³ NC⁻¹
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Magnetic Effects of Current and Magnetism
(167)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The electron of a hydrogen atom revolves round the proton in a circular
- A particle moves along the x-axis such that its co-ordinate (x) varies with time (t)
- A transformer rated at 10 kW is used to connect a 5 kV transmission line to a 240 V
- To measure the roughness of the surface of a material, which of the following microscope
- A car moving with a speed of 50 kmh⁻¹ can be stopped by brakes after at least 6 m
Topics: Magnetic Effects of Current and Magnetism (167)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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Using v=EB,
we have , E = v B
E =(2×103)1.5
E =3×103NC−1