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A marble block of mass 2 kg lying on ice when given a velocity of 6 m/s is stopped by friction in 10 sec. Then the coefficient of friction is
Options
(a) 0.01
(b) 0.02
(c) 0.03
(d) 0.06
Correct Answer:
0.06
Explanation:
From equation of motion, v = u – at
⇒ o = u – μgt
⇒ μ = u/gt
= 6/(10×10)
= 0.06
Related Questions: - Pick out the statement ehich is incorrect?
- Two cells when connected in series are balanced on 8m on a potentiometer.
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Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Pick out the statement ehich is incorrect?
- Two cells when connected in series are balanced on 8m on a potentiometer.
- The work function for metals A,B abd C are respectively 1.92 eV,2.0 eV and 5 eV.
- The length of second pendulum is 1 m on earth. If mass and diameter
- Before using the tangent galvanometer, its coil is set in
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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