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A marble block of mass 2 kg lying on ice when given a velocity of 6 m/s is stopped by friction in 10 sec. Then the coefficient of friction is
Options
(a) 0.01
(b) 0.02
(c) 0.03
(d) 0.06
Correct Answer:
0.06
Explanation:
From equation of motion, v = u – at
⇒ o = u – μgt
⇒ μ = u/gt
= 6/(10×10)
= 0.06
Related Questions: - At what temperature will the rms speed of air molecules be double that of NTP?
- Which of the following is a vector quantity?
- A tuning fork A produces 4 beats per second with another tuning fork B of frequency
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Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- At what temperature will the rms speed of air molecules be double that of NTP?
- Which of the following is a vector quantity?
- A tuning fork A produces 4 beats per second with another tuning fork B of frequency
- A wheel has moment of inertia 5 x 10⁻³ kgm² and is making 20 revolutions per sec
- A soap bubble oscillates with time period T, which in turn depends on the pressure
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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