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A marble block of mass 2 kg lying on ice when given a velocity of 6 m/s is stopped by friction in 10 sec. Then the coefficient of friction is
Options
(a) 0.01
(b) 0.02
(c) 0.03
(d) 0.06
Correct Answer:
0.06
Explanation:
From equation of motion, v = u – at
⇒ o = u – μgt
⇒ μ = u/gt
= 6/(10×10)
= 0.06
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Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Cohesive force is experienced between
- A step-down transformer has 50 turns on secondary and 1000 turns on primary winding.
- An ideal gas is compressed to half its initial volume by means of several processes.
- If A=4i+4j+4k and b=3i+j+4k, then angle between vectors A and B is
- A body covers 200 cm in the first 2 seconds and 220 cm in the next 4 seconds.
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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