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A marble block of mass 2 kg lying on ice when given a velocity of 6 m/s is stopped by friction in 10 sec. Then the coefficient of friction is
Options
(a) 0.01
(b) 0.02
(c) 0.03
(d) 0.06
Correct Answer:
0.06
Explanation:
From equation of motion, v = u – at
⇒ o = u – μgt
⇒ μ = u/gt
= 6/(10×10)
= 0.06
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Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Figure below shows two paths that may be taken by a gas to go from a state A
- The radius of the convex surface of a plano-convex lens is 20 cm and the refractive index
- A small oil drop of mass 10⁻⁶kg is hanging in at rest between two plates seperated
- Equal charge q each are placed at the vertices AQ and B of an equilateral triangle
- The velocity of molecules of a gas at temperature 120 K is v. At what temperature
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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