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A marble block of mass 2 kg lying on ice when given a velocity of 6 m/s is stopped by friction in 10 sec. Then the coefficient of friction is
Options
(a) 0.01
(b) 0.02
(c) 0.03
(d) 0.06
Correct Answer:
0.06
Explanation:
From equation of motion, v = u – at
⇒ o = u – μgt
⇒ μ = u/gt
= 6/(10×10)
= 0.06
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Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A 220 volt and 1000 watt bulb is connected across a 110 volt mains supply.
- An electron of a stationary hydrogen atom passes from the fifth energy level to
- A train of mass 2x 10⁵ kg has a constant speed of 20 m/s up a hill inclined
- A charged particle enters a uniform magnetic field with a certain speed at right angles
- In an orbital motion, the angular momentum vector is
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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