| ⇦ |
| ⇨ |
A string is stretched between fixed points seperated by 75 cm. It is observed to have resonant frequencies of 420 Hz and 315 Hz. There are no other resonant frequencies between these two. Then, the lowest resonant frequency for this string is
Options
(a) 10.5 Hz
(b) 105 Hz
(c) 1.05 Hz
(d) 1050 Hz
Correct Answer:
105 Hz
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Rutherford’s α-scattering experiment concludes that
- The kinetic energy needed to project a body of mass m from the surface of earth
- A photon of wavelength 300nm interacts with a stationary hydrogen atom in ground
- The value of Planck’s constant is
- What is the nature of Gaussian surface involved in Gauss’s law of electrostatics?
Topics: Waves
(80)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Rutherford’s α-scattering experiment concludes that
- The kinetic energy needed to project a body of mass m from the surface of earth
- A photon of wavelength 300nm interacts with a stationary hydrogen atom in ground
- The value of Planck’s constant is
- What is the nature of Gaussian surface involved in Gauss’s law of electrostatics?
Topics: Waves (80)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply