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40 g of Argon is heated from 40⁰C to 100⁰C (R=2 cal/mole). Heat absorbed at constant volume is
Options
(a) 100 cal
(b) 80 cal
(c) 180 cal
(d) 120 cal
Correct Answer:
180 cal
Explanation:
Heat absorbed at constant volume = nCvdT
Now argon is monoatomic Cv = (3/2) R
Number of moles = 4/0/40 = 1
.·. Q = 1 × (3/2) × 2 × (100-40) = 3 × 60 = 180 cal.
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A tuning fork of frequency x produces 4 beats with a source of 256 Hz and 8 beats
- A particle moves in xy plane according to the equation x = 4t² + 5t + 16 and y = 5t
- An electron in a circular orbit of radius 0.05 nm performs 10¹⁶ rev/s. The magnetic
- The ionisation energy of an electron in the ground state of helium atom is 24.6 eV.
- The nuclear radius of a certain nucleus is 7.2 fm and it has a charge of 1.28×10⁻¹⁷ C.
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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