| ⇦ | 
| ⇨ |
40 g of Argon is heated from 40⁰C to 100⁰C (R=2 cal/mole). Heat absorbed at constant volume is
Options
(a) 100 cal
(b) 80 cal
(c) 180 cal
(d) 120 cal
Correct Answer:
180 cal
Explanation:
Heat absorbed at constant volume = nCvdT
Now argon is monoatomic Cv = (3/2) R
Number of moles = 4/0/40 = 1
.·. Q = 1 × (3/2) × 2 × (100-40) = 3 × 60 = 180 cal.
Related Questions: - In a thermodynamic system, working substance is ideal gas. Its internal energy
- In a transistor, the value of βis 100, then the value of α will be
- The voltage of clouds is 4×10⁶ volt with respect to ground. In a lightening
- If the velocity of an electron increases, then its de Broglie wavelength will
- A particle of mass m moves with constant speed along a circular path of radius r under
Topics: Thermodynamics
(179)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In a thermodynamic system, working substance is ideal gas. Its internal energy
- In a transistor, the value of βis 100, then the value of α will be
- The voltage of clouds is 4×10⁶ volt with respect to ground. In a lightening
- If the velocity of an electron increases, then its de Broglie wavelength will
- A particle of mass m moves with constant speed along a circular path of radius r under
Topics: Thermodynamics (179)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply