⇦ | ⇨ |
A particle moves with constant speed v along a circular path of radius r and completes the circle in time T. The acceleration of the particle is
Options
(a) 2πv/T
(b) 2πr/T
(c) 2πr²/T
(d) 2πv²/T
Correct Answer:
2πv/T
Explanation:
Centripetal acceleration = v² / R = v × (v/R) a = v × ω (Therefore, ω = v/R) a = (v × 2π)/T.
Related Questions: - Ring, hollow ring and solid sphere are rolled down from inclined plane
- The magnetic susceptibility is negative for
- The wavelength of first line of Balmer series is 6563Å. The wavelength of first line
- If fundamental frequency of closed pipe is 50 Hz then frequency of 2nd overtone
- The primary and secondary coil of the transformer have 50 and 1500 turns respectively
Topics: Motion in Plane
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Ring, hollow ring and solid sphere are rolled down from inclined plane
- The magnetic susceptibility is negative for
- The wavelength of first line of Balmer series is 6563Å. The wavelength of first line
- If fundamental frequency of closed pipe is 50 Hz then frequency of 2nd overtone
- The primary and secondary coil of the transformer have 50 and 1500 turns respectively
Topics: Motion in Plane (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply