| ⇦ | 
| ⇨ |
A common emitter amplifier is designed with n-p-n transistor (α=0.99). The input impedence is 1kΩ and load is 10kΩ. The voltage gain will be
Options
(a) 9900
(b) 99
(c) 9.9
(d) 990
Correct Answer:
990
Explanation:
Voltage gain = β × Resistance gain
β = α/(1-α) = 0.99 / (1-0.99) = 99
Resistance gain = (10 × 10³) = 10
Voltage gain = 99 × 10 = 990
Related Questions: - Two cities are 150 km apart. Electric power is sent from one city to another city
- The threshold frequency for a photosensitive metal is 3.3 x 10¹⁴ Hz.
- In atom bomb, the reaction which occurs is
- An electric current passes through a long straight wire
- Thomson coefficient of a conductor is 10 µV/K. Its two ends are kept
Topics: Electronic Devices
(124)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two cities are 150 km apart. Electric power is sent from one city to another city
- The threshold frequency for a photosensitive metal is 3.3 x 10¹⁴ Hz.
- In atom bomb, the reaction which occurs is
- An electric current passes through a long straight wire
- Thomson coefficient of a conductor is 10 µV/K. Its two ends are kept
Topics: Electronic Devices (124)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply