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A common emitter amplifier is designed with n-p-n transistor (α=0.99). The input impedence is 1kΩ and load is 10kΩ. The voltage gain will be
Options
(a) 9900
(b) 99
(c) 9.9
(d) 990
Correct Answer:
990
Explanation:
Voltage gain = β × Resistance gain
β = α/(1-α) = 0.99 / (1-0.99) = 99
Resistance gain = (10 × 10³) = 10
Voltage gain = 99 × 10 = 990
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Topics: Electronic Devices
(124)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A ballon rises from rest with a constant acceleration g/8. A stone is released
- A force acts on a 3.0 g particle in such a way that the position of the particle
- For a series L-C-R circuit, the rms values of voltage across various components
- A particle moves with constant speed v along a circular path of radius r and completes
- Young’s modulus of the material of a wire is 18×10¹¹ dyne cm⁻².its value in SI is
Topics: Electronic Devices (124)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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