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A common emitter amplifier is designed with n-p-n transistor (α=0.99). The input impedence is 1kΩ and load is 10kΩ. The voltage gain will be
Options
(a) 9900
(b) 99
(c) 9.9
(d) 990
Correct Answer:
990
Explanation:
Voltage gain = β × Resistance gain
β = α/(1-α) = 0.99 / (1-0.99) = 99
Resistance gain = (10 × 10³) = 10
Voltage gain = 99 × 10 = 990
Related Questions: - A solenoid 1.5 m long and 0.4 cm in diameter possesses 10 turns per cm length
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Topics: Electronic Devices
(124)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A solenoid 1.5 m long and 0.4 cm in diameter possesses 10 turns per cm length
- 24 cells of emf 1.5 V each having internal resistance of 1 ohm are connected
- Which one of the following statements is not correct in case of a semiconductor?
- For a simple pendulum performing simple harmonic motion, the time period
- If particles are moving with same velocity, then maximum de Broglie wavelength will
Topics: Electronic Devices (124)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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