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A radioactive substance decays to 1/16th of its initial activity in 40 days. The half-life of the radioactive substance expressed in days is
Options
(a) 2.5
(b) 5
(c) 10
(d) 20
Correct Answer:
10
Explanation:
N/N₀ = (1/2)ⁿ
(1/16) = (1/2)ⁿ
n = 4
Half life = t / n = 40 / 4 = 10 day
Related Questions: - The electric potential at a point in free space due to a charge Q coulomb is Q x 10¹¹ v
- ₉₂U²³⁴ has 92 protons and 238 nucleons. It decays by emitting an alpha particle
- If a proton, a deuteron and an alpha particle, on being accelerated by the same
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Topics: Radioactivity
(83)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The electric potential at a point in free space due to a charge Q coulomb is Q x 10¹¹ v
- ₉₂U²³⁴ has 92 protons and 238 nucleons. It decays by emitting an alpha particle
- If a proton, a deuteron and an alpha particle, on being accelerated by the same
- A glass flask weighing 390 g having internal volume 500 cc just floats
- If (range)² is 48 times (maximum height)², then angle of projection is
Topics: Radioactivity (83)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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