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A radioactive substance decays to 1/16th of its initial activity in 40 days. The half-life of the radioactive substance expressed in days is
Options
(a) 2.5
(b) 5
(c) 10
(d) 20
Correct Answer:
10
Explanation:
N/N₀ = (1/2)ⁿ
(1/16) = (1/2)ⁿ
n = 4
Half life = t / n = 40 / 4 = 10 day
Related Questions: - Copper has face centered cubic (fcc) lattice with interatomic spacing equal to 2.54Å.
- On heating a ferromagnetic substance above curie temperature
- A copper disc of radius 0.1 m is rotated about its centre, with 10 revolutions
- A particle moves in xy plane according to the equation x = 4t² + 5t + 16 and y = 5t
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Topics: Radioactivity
(83)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Copper has face centered cubic (fcc) lattice with interatomic spacing equal to 2.54Å.
- On heating a ferromagnetic substance above curie temperature
- A copper disc of radius 0.1 m is rotated about its centre, with 10 revolutions
- A particle moves in xy plane according to the equation x = 4t² + 5t + 16 and y = 5t
- The net electric force on a charge of +3μC at the mid-point on the line joining two
Topics: Radioactivity (83)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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