| ⇦ |
| ⇨ |
A uniform rod of length l is placed with one end in contact with the horizontal and is then inclined at an angle α to the horizontal and allowed to fall, without slipping at contact point. When it becomes horizontal, its angular velocity will be
Options
(a) ? = √3gsin α/l
(b) ? = √2l/3gsin α
(c) ? = √6gsin α/l
(d) ? = √l/gsin α
Correct Answer:
? = √3gsin α/l
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - A short magnet of magnetic moment M, is placed on a straight line. The ratio
- Two particles of masses m₁ m₂ move with initial velocities u₁ and u₂
- An α-particle of energy 5 MeV is scattered through 180⁰ by a fixed uranium nucleus.
- In a uniform circular motion,
- Shear modulus is zero for
Topics: Motion of system of Particles and Rigid Body
(73)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A short magnet of magnetic moment M, is placed on a straight line. The ratio
- Two particles of masses m₁ m₂ move with initial velocities u₁ and u₂
- An α-particle of energy 5 MeV is scattered through 180⁰ by a fixed uranium nucleus.
- In a uniform circular motion,
- Shear modulus is zero for
Topics: Motion of system of Particles and Rigid Body (73)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply