| ⇦ | 
| ⇨ |
Two springs with spring constants K₁=1500 N/m and K₂=3000 N/m are stretched by the same force. The ratio of potential energy stored in springs will be
Options
(a) 1:2
(b) 2:1
(c) 4:1
(d) 1:4
Correct Answer:
2:1
Explanation:
Force F=-Kxdisplacement (x),
Potential Energy = U =(1/2) Kx²
U = (1/2) K(F/K)² = (1/2)(F²/K)
U₁/U₂=(1/2)(F²/K₁)x(2K₂/F²)
K₂/K₁=3000/1500=2/1.
Related Questions: - A solid body rotates about a stationary axis, so that its angular velocity
- A bimetallic strip consists of metals X and Y. It is mounted rigidly at the base as shown
- A plane polarised light is incident normally on a tourmaline plate. Its E vector make
- A mixture consists of two radioactive materials A₁ and A₂ with half lives of 20s
- Minimum and maximum values of Poisson’s ratio for a metal lies between
Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A solid body rotates about a stationary axis, so that its angular velocity
- A bimetallic strip consists of metals X and Y. It is mounted rigidly at the base as shown
- A plane polarised light is incident normally on a tourmaline plate. Its E vector make
- A mixture consists of two radioactive materials A₁ and A₂ with half lives of 20s
- Minimum and maximum values of Poisson’s ratio for a metal lies between
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply