| ⇦ |
| ⇨ |
A body of mass 3 kg acted upon by a constant force is displaced by S meter, given by relation S=1/3t², where t is in second. Work done by the force in2 seconds
Options
(a) 8/3 J
(b) 19/5 J
(c) 5/19 J
(d) 3/8 J
Correct Answer:
8/3 J
Explanation:
S = (1/3) t²; v = dS / dt = (2/3) t
a = d²S / dt² = 2/3
F = ma = 3 × (2/3) = 2N
Work = 2 × (1/3) t²
At t = 2 seconds
.·. Work = 2 × (1/3) × 2 × 2 = (8/3) J
Related Questions: - A particle of mass 1.96×10⁻¹⁵ kg is kept in equilibrium between two horizontal metal
- The ratio of magnetic dipole moment of an electron of charge e and mass m
- A car of mass m is moving on a level circular track of radius R
- Two identical cells of the same e.m.f. and same internal resistance
- A wheel has moment of inertia 5 x 10⁻³ kgm² and is making 20 revolutions per sec
Topics: Work Energy and Power
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A particle of mass 1.96×10⁻¹⁵ kg is kept in equilibrium between two horizontal metal
- The ratio of magnetic dipole moment of an electron of charge e and mass m
- A car of mass m is moving on a level circular track of radius R
- Two identical cells of the same e.m.f. and same internal resistance
- A wheel has moment of inertia 5 x 10⁻³ kgm² and is making 20 revolutions per sec
Topics: Work Energy and Power (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply