| ⇦ | 
| ⇨ |
If a carnot engine is working with source temperature at 227⁰C and sink temperature at 27⁰C, its efficiency will be
Options
(a) 40%
(b) 10%
(c) 67%
(d) 50%
Correct Answer:
40%
Explanation:
Efficiency of a Carnot engine η = 1 – (T₂ / T₁)
where T₁ is the temperature of the source and T₂ is the temperature of the sink.
Here, T₁ = 227°C = 500 K
T₂ = 27°C = 300 K
.·. η = 1 – (300/500) = 2/5 = 40 %.
Related Questions: - An amplifier has a voltage gain Av=1000. The voltage gain in dB is
- 34 gram of water at 30⁰C is poured into a calorimeter at 15⁰C.
- A rod of weight W is supported by two parallel knife edge A and B
- A body is hangfing from a rigid support by an inextensible string of length
- Magnetic flux φ (in weber) linked with a closed circuit of resistance 10 Ω varies
Topics: Thermodynamics
(179)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- An amplifier has a voltage gain Av=1000. The voltage gain in dB is
- 34 gram of water at 30⁰C is poured into a calorimeter at 15⁰C.
- A rod of weight W is supported by two parallel knife edge A and B
- A body is hangfing from a rigid support by an inextensible string of length
- Magnetic flux φ (in weber) linked with a closed circuit of resistance 10 Ω varies
Topics: Thermodynamics (179)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply