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If a carnot engine is working with source temperature at 227⁰C and sink temperature at 27⁰C, its efficiency will be
Options
(a) 40%
(b) 10%
(c) 67%
(d) 50%
Correct Answer:
40%
Explanation:
Efficiency of a Carnot engine η = 1 – (T₂ / T₁)
where T₁ is the temperature of the source and T₂ is the temperature of the sink.
Here, T₁ = 227°C = 500 K
T₂ = 27°C = 300 K
.·. η = 1 – (300/500) = 2/5 = 40 %.
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Topics: Thermodynamics
(179)
Subject: Physics
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Unit of electrical conductivity is
- When a ceiling fan is switched off its angular velocity reduces to 50% while
- A cricketer can throw a ball to a maximum horizontal distance of 100 m. With the same
- A steady current of 1.5 amp flows through a copper voltmeter for 10 minutes
- The ratio of specific heats Cp/Cv=γ in terms of degrees of freedom (n) is given by
Topics: Thermodynamics (179)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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