| ⇦ |
| ⇨ |
An object is attached to the bottom of a light vertical spring and set vibrating. The maximum speed of the object is 15cm/sec and the period is 628 mili-sec. The amplitude of the motion in cm is
Options
(a) 3
(b) 2
(c) 1.5
(d) 1
Correct Answer:
1.5
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The electric field part of an electromagnetic wave in a medium is represented by
- If |A x B|= √3 A.B , then the value of |A + B| is
- A light whose frequency is equal to 6.0 x 10¹⁴ Hz is incident on a metal
- A long horizontal rod has a bead which can slide long its length
- A carnot engine working between 300 K and 600 K has a work output of 800J per cycle.
Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The electric field part of an electromagnetic wave in a medium is represented by
- If |A x B|= √3 A.B , then the value of |A + B| is
- A light whose frequency is equal to 6.0 x 10¹⁴ Hz is incident on a metal
- A long horizontal rod has a bead which can slide long its length
- A carnot engine working between 300 K and 600 K has a work output of 800J per cycle.
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Vmax=Aω A=v/ω ω=2π/T ω=2*3.14/628*10^-3 ω=10 A=15/10 A=1.5