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A rod of 10 cm length is moving perpendicular to uniform magntic field of intensity 5×10⁻⁴Wbm⁻². If the acceleration of the rod is 5ms⁻¹, then the rate of increase of induced emf is
Options
(a) 25×10⁻⁴ Vs⁻¹
(b) 2.5×10⁻⁴ Vs⁻¹
(c) 2.0×10⁻⁴ Vs⁻¹
(d) 20×10⁻⁴ Vs⁻¹
Correct Answer:
2.5×10⁻⁴ Vs⁻¹
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Electromagnetic Induction
(76)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Which of the following physical quantities has neither dimensions nor unit
- A particle of mass m is projected with a velocity v making an angle of 45°
- A concave mirror of focal length f₁ is placed at a distance d from a convex lens
- The moment of inertia of a thin circular disc about an axis passing through its centre
- In a series resonant LCR circuit, the voltage across R is 100 volts and R =1kΩ
Topics: Electromagnetic Induction (76)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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