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A rod of 10 cm length is moving perpendicular to uniform magntic field of intensity 5×10⁻⁴Wbm⁻². If the acceleration of the rod is 5ms⁻¹, then the rate of increase of induced emf is
Options
(a) 25×10⁻⁴ Vs⁻¹
(b) 2.5×10⁻⁴ Vs⁻¹
(c) 2.0×10⁻⁴ Vs⁻¹
(d) 20×10⁻⁴ Vs⁻¹
Correct Answer:
2.5×10⁻⁴ Vs⁻¹
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Electromagnetic Induction
(76)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Under the action of a force F=cx, the position of a body changes from 0 to x.The work done
- The wavelength of the short radio waves, microwaves, ultraviolet waves are λ₁,λ₂ and λ₃
- The displacement ‘x’ (in meter) of a particle of mass ‘m’ (in kg) moving in one
- Masses of three wires of copper are in the ratio of 1:3:5 and their lengths
- If c is the velocity of light in free space, the time taken by light to travel
Topics: Electromagnetic Induction (76)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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