| ⇦ |
| ⇨ |
A conductor of length 5 cm is moved parallel to itself with a speed of 2 m/s, perpendicular to a uniform magnetic field of 10⁻³ Wb/m². The induced emf generated is
Options
(a) 2×10⁻³ V
(b) 1×10⁻³ V
(c) 1×10⁻⁴ V
(d) 2×10⁻⁴ V
Correct Answer:
1×10⁻⁴ V
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Pick out the correct statements from the following
- When a ball is thrown up vertically with velocity vₒ,it reaches a maximum height
- 64 drops of mercury, each charged to a potential of 10 V, are combined
- A body of mass m is accelerated uniformly from rest to a speed v in a time T
- An adiabatic process occurs at constant
Topics: Electromagnetic Induction
(76)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Pick out the correct statements from the following
- When a ball is thrown up vertically with velocity vₒ,it reaches a maximum height
- 64 drops of mercury, each charged to a potential of 10 V, are combined
- A body of mass m is accelerated uniformly from rest to a speed v in a time T
- An adiabatic process occurs at constant
Topics: Electromagnetic Induction (76)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply