| ⇦ |
| ⇨ |
A mass of 2.0 kg is put on a flat plan attached to a vertical spring fixed on the ground as shown in the figure. The mass of the spring and the pan is negligible. When pressed slightly and released the mass executes a simple harmonic motion. The spring constant is 200 N/m. What should be the minimum amplitude of the motion so that the mass gets detached from the pan (take g=10 m/s²)
Options
(a) 10.0 cm
(b) Any value less than 12.0 cm
(c) 4.0 CM
(d) 8.0 CM
Correct Answer:
10.0 cm
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - A block of 2 kg is kept on the floor. The coefficient of static friction is 0.4
- We get Balmer series when electron comes from
- SI unit of magnetic dipole moment is
- If a body travels half the distance with velocity v1 and the next half with velocity v2
- Frequency of stretched string will increase by
Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A block of 2 kg is kept on the floor. The coefficient of static friction is 0.4
- We get Balmer series when electron comes from
- SI unit of magnetic dipole moment is
- If a body travels half the distance with velocity v1 and the next half with velocity v2
- Frequency of stretched string will increase by
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply