A photon of energy 10.2 eV collide inelastically with hydrogen atom in ground state

⇦

⇨

A photon of energy 10.2 eV collide inelastically with hydrogen atom in ground state after few microseconds another photon of energy 15 eV collides inelastically with same hydrogen atom. Finally by a suitable detector we find

Options

(a) photon of energy 3.4 eV and electron of energy 1.4 eV
(b) photon of energy 10.2 eV and electron of energy 1.4 eV
(c) two photons of energy 3.4 eV
(d) two photons of energy 10.2 eV

Correct Answer:

photon of energy 10.2 eV and electron of energy 1.4 eV

Explanation:

No explanation available. Be the first to write the explanation for this question by commenting below.

Related Questions:

1. Two cells, having the same e.m.f. are connected in series through an external resistance
2. A car of mass 1000 kg negotiates a banked curve of radius 90 m on a frictionless
3. A bullet of mass m moving with velocity v strikes a block of mass M at rests
4. Calculate the focal length of a reading glass of a person, if the distance
5. A simple pendulum has a time period T₁ when on the earth’s surface and T₂ When taken

Topics: Atoms and Nuclei (136)
Subject: Physics (2479)

---

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

---

Share this page with your friends