| ⇦ |
| ⇨ |
A spring of spring constant 5 x 10³ Nm⁻¹ is streched intially by 5 cm from the unstreched position.Then, the work required to strech it further by another 5 cm is
Options
(a) 12.50 cm
(b) 18.75 Nm
(c) 25.00 Nm
(d) 6.25 Nm
Correct Answer:
18.75 Nm
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The length of second pendulum is 1 m on earth. If mass and diameter
- A,B and C are voltmeters of resistance R, 1.5 R and 3R respectively, as shown
- A hollow metal sphere of radius 10 cm is charged such that the potential on its surface
- Two bodies of masses m and 4 m are moving with equal K.E. The ratio of their linear
- If F⃗ is the force acting on a particle having position vector r⃗ and ? ⃗ be the torque
Topics: Work Energy and Power
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The length of second pendulum is 1 m on earth. If mass and diameter
- A,B and C are voltmeters of resistance R, 1.5 R and 3R respectively, as shown
- A hollow metal sphere of radius 10 cm is charged such that the potential on its surface
- Two bodies of masses m and 4 m are moving with equal K.E. The ratio of their linear
- If F⃗ is the force acting on a particle having position vector r⃗ and ? ⃗ be the torque
Topics: Work Energy and Power (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply