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A uniform force of (3i + j) newton acfs on a particle of mass 2kg. The particle is displaced from position (2i + k) meter to position (4i + 3j – k) meter. The work done by the force on the particle is
Options
(a) 6 J
(b) 13 J
(c) 15 J
(d) 9 J
Correct Answer:
9 J
Explanation:
Given : F⃗ = 3i + j
r⃗₁ = (2i + k), r⃗₂ = (4i + 3j – k⃗)
r⃗ = r⃗₂ – r⃗₁ = (4i + 3j – k⃗) – (2i + k)
or r⃗ = 2i + 3j – 2k
so, work done by the given force w = f⃗ . r⃗
= (3i + j) x (2i + 3j – 2k) = 6 + 3 = 9 J
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Topics: Work Energy and Power
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The wavelength of the first line of Lymasn series for hydrogen atom is equal
- For non-conductors, the energy gap is
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- A concave lens of focal length f forms an image which is 1/3 times the size
- Two stones of masses m and 2m are whirled in horizontal circles, the heavier one
Topics: Work Energy and Power (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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