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The drive shaft of an automobile rotates at 3600 rpm and transmits 80 HP up from the engine to the rear wheels.The torque developed by the engine is
Options
(a) 16.58 Nm
(b) 0.022 Nm
(c) 158.31 Nm
(d) 141.6 Nm
Correct Answer:
158.31 Nm
Explanation:
P = τω ⇒ τ = P/ω Given:- P = 80 HP = 80 x 746W = 59860 Nms⁻¹ ω = 3600 rpm = (3600/60) x 2π rad s⁻¹ = 120 π rad s⁻¹ τ = 59680/(120xπ) =158.31 Nm
Related Questions: - Cathode rays are produced when the pressure is of the order of
- Length of second pendulum is
- A gas is suddenly expanded such that its final volume becomes 3 times
- When a ball is thrown up vertically with velocity vₒ,it reaches a maximum height
- A particle of mass 100g tied to a string is rotated along a circle of radius 0.5 m
Topics: Motion in Plane
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Cathode rays are produced when the pressure is of the order of
- Length of second pendulum is
- A gas is suddenly expanded such that its final volume becomes 3 times
- When a ball is thrown up vertically with velocity vₒ,it reaches a maximum height
- A particle of mass 100g tied to a string is rotated along a circle of radius 0.5 m
Topics: Motion in Plane (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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