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The drive shaft of an automobile rotates at 3600 rpm and transmits 80 HP up from the engine to the rear wheels.The torque developed by the engine is
Options
(a) 16.58 Nm
(b) 0.022 Nm
(c) 158.31 Nm
(d) 141.6 Nm
Correct Answer:
158.31 Nm
Explanation:
P = τω ⇒ τ = P/ω Given:- P = 80 HP = 80 x 746W = 59860 Nms⁻¹ ω = 3600 rpm = (3600/60) x 2π rad s⁻¹ = 120 π rad s⁻¹ τ = 59680/(120xπ) =158.31 Nm
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Topics: Motion in Plane
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The atomic number of the most common element in nuclear fusion is
- The dimensions of Planck’s constant is same as that of
- A radioactive substance decays to 1/16th of its initial activity in 40 days.
- At what angle should the two forces 2P and √2 P act,so that the resultant force is P√10?
- If force(F), Velocity(V) and time(T) are taken as fundamental units, then the dimensions
Topics: Motion in Plane (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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