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The drive shaft of an automobile rotates at 3600 rpm and transmits 80 HP up from the engine to the rear wheels.The torque developed by the engine is
Options
(a) 16.58 Nm
(b) 0.022 Nm
(c) 158.31 Nm
(d) 141.6 Nm
Correct Answer:
158.31 Nm
Explanation:
P = τω ⇒ τ = P/ω Given:- P = 80 HP = 80 x 746W = 59860 Nms⁻¹ ω = 3600 rpm = (3600/60) x 2π rad s⁻¹ = 120 π rad s⁻¹ τ = 59680/(120xπ) =158.31 Nm
Related Questions: - If the length of a closed organ pipe is 1.5 m and velocity of sound is 330 m/s,
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Topics: Motion in Plane
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If the length of a closed organ pipe is 1.5 m and velocity of sound is 330 m/s,
- When a mass M is attached to the spring of force constant k,
- The threshold wavelength for photoelectric emission from a material is 4800 Å.
- A solenoid 1.5 m long and 0.4 cm in diameter possesses 10 turns per cm length
- If a nucleus ᴢXᴬ emits 9α and 5β-particles, then the ratio of total protons and neutrons
Topics: Motion in Plane (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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