| ⇦ |
| ⇨ |
An open knife edge of mass 200g is dropped from height 5m on a cardboard. If the knife edge penetrates distance 2m into the cardboard, the average resistance offered by the cardboard to the knife edge is
Options
(a) 7N
(b) 25N
(c) 35N
(d) None of these
Correct Answer:
7N
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - In an AC generator, a coil with N turns, all of the same area A and total resistance R,
- Find out the angle of projection, if range is 4 times of maximum height
- The most important characteristic of electron in the production of X-rays is
- The horizontal component of earth’s magnetic field at a place is 3×10⁻⁴ T
- Figure below shows two paths that may be taken by a gas to go from a state A
Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In an AC generator, a coil with N turns, all of the same area A and total resistance R,
- Find out the angle of projection, if range is 4 times of maximum height
- The most important characteristic of electron in the production of X-rays is
- The horizontal component of earth’s magnetic field at a place is 3×10⁻⁴ T
- Figure below shows two paths that may be taken by a gas to go from a state A
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

We can use work energy theorem ,
Total kinetic energy lost is K=mg(h+d)
Work done by the resistance force F is W=Fd
By equating , we get Force =
mg(h+d)/d = [{(200/1000)×(5+2)}/2] N = [0.2×7÷2] N = 7N (ans)