| ⇦ |
| ⇨ |
The motion of a particle along a straight line is described by equation : x= 8 + 12t– t³ where x is in metre and t in second. The retardation of the particle when its velocity becomes zero, is :
Options
(a) 24 ms⁻²
(b) zero
(c) 6ms⁻²
(d) 12 ms⁻²
Correct Answer:
12 ms⁻²
Explanation:
x = 8 + 12t – t³ The final velocity of the particle will be zero, because it retarded.
V= 0 + 12 – 3t² = 0 ⇒ 3t² = 12 ⇒ t = 2 sec
Now the retardation a = dv/ dt = 0 – 6t
a [ t= 2] = – 12 m/s²
retardation = 12 m/s²
Related Questions: - A body undergoes no change in volume. Poisson’s ratio is
- Source S₁ is producing, 10¹⁵ photons per second of wavelength 5000Å
- The resistances of the four arms P,Q,R and S in a Wheatstone’s bridge
- An atom bomb weighing 1 kg explodes releasing 9×10¹³ J of energy.
- The maximum particle velocity in a wave motion is half the wave velocity.
Topics: Motion in Straight Line
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A body undergoes no change in volume. Poisson’s ratio is
- Source S₁ is producing, 10¹⁵ photons per second of wavelength 5000Å
- The resistances of the four arms P,Q,R and S in a Wheatstone’s bridge
- An atom bomb weighing 1 kg explodes releasing 9×10¹³ J of energy.
- The maximum particle velocity in a wave motion is half the wave velocity.
Topics: Motion in Straight Line (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply