| ⇦ | 
| ⇨ |
A particle moves along with x-axis.The position x of particle with respect to time t from origin is given by x=bₒ+b₁t+b₂t².The acceleration of particle is
Options
(a) bₒ
(b) b₁
(c) b₂
(d) 2b₂
Correct Answer:
2b₂
Explanation:
Given, x=b₀+b₁t+b₂t²
Also, v=dx/dt=d/dt(b₀+b₁t+b₂t²)
Using (d/dx).xⁿ=nxⁿ⁻¹, we have
v=b₁+2b₂t
The Acceleration is,
a=dv/dt=d/dt(b₁+2b₂t)
=2b₂
Another Explanation:
Distance , x = b₀ + b₁t + b₂t²
velocity , v = (dx / dt ) = b₁ + 2b₂t
Acceleration, α = d²x / dt² = 2 b₂.
Related Questions: - If the ratio of amplitude of two superposed waves is 2:1, then the ratio of maximum
- Bragg’s law for X-rays is
- Choose the correct statement
- An object is projected with a velocity of 20 m/s making an angle of 45⁰ with horizontal.
- Two Carnot engine A and B are operated in series. The engine A receives
Topics: Motion in Straight Line
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If the ratio of amplitude of two superposed waves is 2:1, then the ratio of maximum
- Bragg’s law for X-rays is
- Choose the correct statement
- An object is projected with a velocity of 20 m/s making an angle of 45⁰ with horizontal.
- Two Carnot engine A and B are operated in series. The engine A receives
Topics: Motion in Straight Line (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply