| ⇦ | 
| ⇨ |
The string of a pendulum is horizontal.The mass of bob attached to it is m.Now, the string is released.The tension in the string in the lowest position is
Options
(a) mg
(b) 2 mg
(c) 3 mg
(d) 4 mg
Correct Answer:
3 mg
Explanation:
When string is released, then according to conservation of energy,
(1/2) mv² = mgh
v² = 2gh = 2gR
Now, when it is at the bottom,
T – mg cos 0² = mv²/R
or T – mg = (m/R)(2gR)
T = mg + 2mg = 3mg.
Related Questions: - A body of mass 10 kg is moving on an inclined plane of inclination 30°with an acceleration
- The earth is assumed to be a sphere of radius R. A platform is arranged at a height R
- In a laser tube, all the photons
- Calculate the charge on equivalent capacitance of the conbination shown in figure
- The core of a transformer is laminated because
Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A body of mass 10 kg is moving on an inclined plane of inclination 30°with an acceleration
- The earth is assumed to be a sphere of radius R. A platform is arranged at a height R
- In a laser tube, all the photons
- Calculate the charge on equivalent capacitance of the conbination shown in figure
- The core of a transformer is laminated because
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply