If ₉₂U²³⁸ undergoes successively 8 ∝-decays and 6 β-decays, the resulting nucleus is

If U Undergoes Successively 8 Decays And 6 Decays The Physics Question

If ₉₂U²³⁸ undergoes successively 8 ∝-decays and 6 β-decays, the resulting nucleus is

Options

(a) ₉₂U²⁰⁸
(b) ₉₂Pb²⁰⁶
(c) ₉₂U²¹⁰
(d) ₉₂U²¹⁴

Correct Answer:

₉₂Pb²⁰⁶

Explanation:

No explanation available. Be the first to write the explanation for this question by commenting below.

Related Questions:

  1. If an electron and a positron annihilate, the energy released is
  2. α-particles, deuterons and protons of same energy are moving in a perpendicular
  3. For a satellite moving in an orbit around the earth, the ratio of kinetic
  4. A string is stretched between fixed points seperated by 75 cm. It is observed
  5. If two soap bubbles of different radii are connected by a tube

Topics: Radioactivity (83)
Subject: Physics (2479)

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

NEETLab Mobile App

Share this page with your friends

Be the first to comment

Leave a Reply

Your email address will not be published.


*