| ⇦ | 
| ⇨ |
The total energy of a particle executing SHM is 80 J. What is the potential energy when the particle is at a distance of 3/4 of amplitude from mean position
Options
(a) 60 J
(b) 10 J
(c) 40 J
(d) 45 J
Correct Answer:
45 J
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Two identical circular coils A and B are kept on a horizontal tube
- Which of the following figures represent the variation of particle momentum
- A rod of weight W is supported by two parallel knife edges A and B is in equilibrium
- If the angular momentum of any rotating body increase by 200 % , then the increase
- In a transistor, the value of βis 100, then the value of α will be
Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two identical circular coils A and B are kept on a horizontal tube
- Which of the following figures represent the variation of particle momentum
- A rod of weight W is supported by two parallel knife edges A and B is in equilibrium
- If the angular momentum of any rotating body increase by 200 % , then the increase
- In a transistor, the value of βis 100, then the value of α will be
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
U = 80 sin2 x sin-3/4
= 80 x 9
————–
16
=45 J