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A light whose frequency is equal to 6.0 x 10¹⁴ Hz is incident on a metal whose work function is 2 eV. (h= 6.63 x 10⁻³⁴ Js, 1 ev = 1.6 x 10⁻¹⁹ J). The maximum energy of the electron emitted will be
Options
(a) 2.49 eV
(b) 4.49 eV
(c) 0.49 eV
(d) 5.49 eV
Correct Answer:
0.49 eV
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In a semiconductor
- If the angular momentum of any rotating body increase by 200 % , then the increase
- A ball rolls off the top of stair way with a horizontal velocity of magnitude 1.8 m/s
- The mass of a ⁷₃ Li nucleus is 0.042 u less than the sum of the masses of all its nucleons
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Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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