| ⇦ | 
| ⇨ |
A light whose frequency is equal to 6.0 x 10¹⁴ Hz is incident on a metal whose work function is 2 eV. (h= 6.63 x 10⁻³⁴ Js, 1 ev = 1.6 x 10⁻¹⁹ J). The maximum energy of the electron emitted will be
Options
(a) 2.49 eV
(b) 4.49 eV
(c) 0.49 eV
(d) 5.49 eV
Correct Answer:
0.49 eV
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - A short linear object of length L lies on the axis of a spherical mirror of focal
- After 300 days, the activity of a radioactive sample is 5000 dps
- The energy of a hydrogen atom in the ground state is – 13.6 eV. The energy of a He⁺ ion
- In a region, the potential is represented by V(x,y,z)=6x-8xy-8y+6yz, where V
- At a metro station, a girl walks up a stationary escalator in time t₁
Topics: Dual Nature of Matter and Radiation
(150)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A short linear object of length L lies on the axis of a spherical mirror of focal
- After 300 days, the activity of a radioactive sample is 5000 dps
- The energy of a hydrogen atom in the ground state is – 13.6 eV. The energy of a He⁺ ion
- In a region, the potential is represented by V(x,y,z)=6x-8xy-8y+6yz, where V
- At a metro station, a girl walks up a stationary escalator in time t₁
Topics: Dual Nature of Matter and Radiation (150)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply