| ⇦ | 
| ⇨ |
A resistance of 20 ohm is connected to a source of an alternating potential V=220 sin (100 πt). The time taken by the current to change from its peak value to r.m.s value is
Options
(a) 2.5 x 10⁻³ sec
(b) 0.25 sec
(c) 25 x 10⁻³ sec
(d) 2.5 sec
Correct Answer:
2.5 x 10⁻³ sec
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - In potentiometer experiment, a cell of emf 1.25V gives balancing length of 30 cm
- A plumb line is suspended form a ceiling of a car moving with horizontal acceleration
- A particle moving along X-axis has acceleration f,at time t given by f=fₒ(1- t/T)
- A student performs an experiment to determine the Young’s modulus of a wire
- The half-life period of a radio-active element X is same as the mean life time
Topics: Alternating Current
(96)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In potentiometer experiment, a cell of emf 1.25V gives balancing length of 30 cm
- A plumb line is suspended form a ceiling of a car moving with horizontal acceleration
- A particle moving along X-axis has acceleration f,at time t given by f=fₒ(1- t/T)
- A student performs an experiment to determine the Young’s modulus of a wire
- The half-life period of a radio-active element X is same as the mean life time
Topics: Alternating Current (96)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply