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Bond order of 1.5 is shown by:
Options
(a) O₂⁺
(b) O₂⁻
(c) O₂²⁻
(d) O₂⁻
Correct Answer:
O₂⁻
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Considering entropy (S) as a thermodynamic parameter, the criterion
- The inert form of carbon is
- The oxidation states of sulphur in the anions : SO₃²⁻,S₂O₄²⁻ and S₂O₆²⁻
- In the cyanide ion, the formal negative charge is on
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Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Chemical Bonding and Molecular Structure
(86)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Considering entropy (S) as a thermodynamic parameter, the criterion
- The inert form of carbon is
- The oxidation states of sulphur in the anions : SO₃²⁻,S₂O₄²⁻ and S₂O₆²⁻
- In the cyanide ion, the formal negative charge is on
- NO₂ is not obtained on heating
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Chemical Bonding and Molecular Structure (86)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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