| ⇦ | 
| ⇨ |
0.037g of an alcohol, R-OH was added to C₂H₅Mgl and the has evolved measured 11.2cc at STP. The molecular mass of R-OH will be
Options
(a) 47
(b) 79
(c) 77
(d) 74
Correct Answer:
74
Explanation:
R—OH + C₂H₅Mgl → C₂H₆ + RMgl
0.037 11.2 cc
11.2 cc gas evolved by alcohol= 0.037 g
22400 cc gas will be evolved by alcohol
= 0.037/11.2 x 22400
= 74 g
Related Questions: - The catalyst SnCl₂ / HCl is used in
- For distinguishing phenol and acetic acid we required to react (treat) them
- Aqueous solutions of hydrogen sulphide and sulphur dioxide when mixed together
- In an exothermic reaction
- Be resembles much with
Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Basic Concepts of Chemistry
(94)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The catalyst SnCl₂ / HCl is used in
- For distinguishing phenol and acetic acid we required to react (treat) them
- Aqueous solutions of hydrogen sulphide and sulphur dioxide when mixed together
- In an exothermic reaction
- Be resembles much with
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Basic Concepts of Chemistry (94)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply