| ⇦ | 
| ⇨ |
1.520 g of hydroxide of a metal on ignition gave 0.995 g of oxide. The equivalent weight of metal is
Options
(a) 1.52
(b) 0.995
(c) 190
(d) 9
Correct Answer:
9
Explanation:
One equivalent of the metal reacts with one mole of hydroxide, i.e., 17g
Similarly, one equivalent of the metal reacts with 1/2 mole oxygen atoms, i.e., 8g of oxygen atoms.
Let E be the equivalent mass of the metal. And let x be the number of equivalents of metal hydroxide ignited.
Therefore,
x(E+17) = 1.520g and
x(E+8) = 0.995
Eliminating x, we get E=9.06g.
Related Questions: - Which of the following is a condensation polymer
- Identify the gas which is readily adsorbed by activated charcoal
- The oxidation number of nitrogen in (N₂H₅)⁺ is
- The method of zone refining of metals is based on the principle of
- The rate of reaction between two reactants A and B decreases by a factor of
Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Basic Concepts of Chemistry
(94)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Which of the following is a condensation polymer
- Identify the gas which is readily adsorbed by activated charcoal
- The oxidation number of nitrogen in (N₂H₅)⁺ is
- The method of zone refining of metals is based on the principle of
- The rate of reaction between two reactants A and B decreases by a factor of
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Basic Concepts of Chemistry (94)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply