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At S.T.P the density of CCl₄ vapours in g/L will be nearest to
Options
(a) 6.87
(b) 3.42
(c) 10.26
(d) 4.57
Correct Answer:
6.87
Explanation:
Molecular Weight of CCl₄ = 35.5 + 12 x 4 = 154
1 mole CCl₄ vapour=154 g
According to Avogadro’s hypothesis we know that the molar volume of a gas at STP is 22.4 litres
= 154/22.4 = 6.87
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If principal quantum number n=4, the total number of orbitals having l=3 is
- What is the approximate percentage of H₂O₂ in a sample labelled as 10 V?
- Classical smong is found in
- n-Butane and isobutane are
- The general molecular formula for a cycloalkyl group is
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Basic Concepts of Chemistry (94)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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