| ⇦ | 
| ⇨ |
A particle moves in a circle of radius 5 cm with constant speed and time period 0.2πs. The acceleration of the particle is
Options
(a) 15 m/s²
(b) 25 m/s²
(c) 36 m/s²
(d) 5 m/s²
Correct Answer:
5 m/s²
Explanation:
Centripetal acceleration aᵥ = 𝜔²r
= ( 2π / T)² r
= (2π / 0.2π)² x 5 x 10⁻²
= 5 m/s²
Related Questions: - The order of the electric field near the earth’s surface is
- Two discs of moment of inertia l₁ and I₂ and angular speeds
- A particle of mass 100g tied to a string is rotated along a circle of radius 0.5 m
- If the ionisation energy for the hydrogen atom is 13.6 eV, the energy required
- A long straight wire of radius a carries a steady current I. The current is uniformly
Question Type: Apply
(15)
Difficulty Level: Easy
(1008)
Topics: Motion in Plane
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The order of the electric field near the earth’s surface is
- Two discs of moment of inertia l₁ and I₂ and angular speeds
- A particle of mass 100g tied to a string is rotated along a circle of radius 0.5 m
- If the ionisation energy for the hydrogen atom is 13.6 eV, the energy required
- A long straight wire of radius a carries a steady current I. The current is uniformly
Question Type: Apply (15)
Difficulty Level: Easy (1008)
Topics: Motion in Plane (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply