⇦ | ![]() | ⇨ |
A particle moves in a circle of radius 5 cm with constant speed and time period 0.2πs. The acceleration of the particle is
Options
(a) 15 m/s²
(b) 25 m/s²
(c) 36 m/s²
(d) 5 m/s²
Correct Answer:
5 m/s²
Explanation:
Centripetal acceleration aᵥ = 𝜔²r
= ( 2π / T)² r
= (2π / 0.2π)² x 5 x 10⁻²
= 5 m/s²
Related Questions:
- In Wheatstone bridge, three resistors P,Q and R are conncected in three arms
- A uniform plank of Young’s modulus Y is moved over a smooth horizontal surface
- Given the value of Rydberg constant is 10⁷ m⁻¹, the wave number of the last line
- A thin ring of radius R meter has charge q coulomb uniformly spread on it
- Two thin long conductors seprated by a distance d carry currents
Question Type: Apply
(15)
Difficulty Level: Easy
(1008)
Topics: Motion in Plane
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply