| ⇦ |
| ⇨ |
Young’s modulus of the material of a wire is 18 x 10¹¹ dyne cm⁻². Its value in SI is
Options
(a) 18 x 10¹⁵ Nm⁻²
(b) 18 x 10¹⁰ Nm⁻²
(c) 18 x 10⁹ Nm⁻²
(d) 18 x 10¹² Nm⁻²
Correct Answer:
18 x 10¹⁰ Nm⁻²
Explanation:
1 dyne = 10⁻⁵ Newton
1 cm = 10⁻² m
So, 18 x 10¹¹ x 10⁻⁵ / 10⁻⁴
=18 x 10¹⁰ Nm⁻²
Related Questions: - The escape velocity from the earth’s surface is 11 kms⁻¹.A certain planet
- The S.I. unit of electric flux is
- Three blocks A,B and C of masses 4 kg, 2 kg and 1 kg respectively are in contact
- Which of the following figures represent the variation of particle momentum
- A particle is dropped vertically from rest, from a height.The time taken by it to fall
Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Physical World and Measurement
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The escape velocity from the earth’s surface is 11 kms⁻¹.A certain planet
- The S.I. unit of electric flux is
- Three blocks A,B and C of masses 4 kg, 2 kg and 1 kg respectively are in contact
- Which of the following figures represent the variation of particle momentum
- A particle is dropped vertically from rest, from a height.The time taken by it to fall
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Physical World and Measurement (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply