⇦ | ⇨ |
What will be the ratio of the distance moved by a freely falling body from rest in 4th and 5th seconds of journey?
Options
(a) 4 : 5
(b) 7 : 9
(c) 16 : 25
(d) 1 : 1
Correct Answer:
7 : 9
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The electric potential at a point in free space due to a charge Q coulomb is Q x 10¹¹ v
- Two bodies of mass 0.25 kg each moving towards each other with velocity
- Which pair is isotonic?
- If the magnetising field on a ferromagnetic material is increased, its permeability
- If h is planck’s constant and λ is wavelength, h/λ has dimensions of
Question Type: Apply
(15)
Difficulty Level: Easy
(1008)
Topics: Motion in Plane
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The electric potential at a point in free space due to a charge Q coulomb is Q x 10¹¹ v
- Two bodies of mass 0.25 kg each moving towards each other with velocity
- Which pair is isotonic?
- If the magnetising field on a ferromagnetic material is increased, its permeability
- If h is planck’s constant and λ is wavelength, h/λ has dimensions of
Question Type: Apply (15)
Difficulty Level: Easy (1008)
Topics: Motion in Plane (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
By using,
Snth=u+a/2 (2n-1)=0+a/2 (2×4-1)=7a/2
Again,s=u+a/2 (2n-1)=0+a/2 (2×5-1)=9a/2
Now,S1:S2=7a/2:9a/2=7:9