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A particle has initial velocity (2i⃗+3j⃗) and acceleration (0.3i⃗+0.2j⃗). The magnitude of velocity after 10 seconds will be:
Options
(a) 9 √2 units
(b) 5 √2 units
(c) 5 units
(d) 9 units
Correct Answer:
5 √2 units
Explanation:
v⃗ = u⃗ + a⃗t
v = (2i + 3j) + (0.3i + 0.2j) x 10 = 5i +5j
| v⃗ | = √ (5² + 5²)
| v⃗ | = 5 √2
Related Questions: - A coil of resistance and 1.0 H inductance is connected to an a.c. source of frequency
- Weber ampere per metre is equal to
- Frequency of stretched string will increase by
- In a LCR series circuit, the potential difference between the terminals of the inductor
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Difficulty Level: Easy
(1008)
Topics: Motion in Straight Line
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A coil of resistance and 1.0 H inductance is connected to an a.c. source of frequency
- Weber ampere per metre is equal to
- Frequency of stretched string will increase by
- In a LCR series circuit, the potential difference between the terminals of the inductor
- At place on earth, the vertical component of earth’s magnetic field is √3 times
Difficulty Level: Easy (1008)
Topics: Motion in Straight Line (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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