⇦ | ⇨ |
Standard entropies of X₂, Y₂ and XY₃ are 60, 40 and 50 J K⁻¹ mol⁻¹ respectively. For the reaction 1/2X₂ + 3/2Y₂ ⇌ XY₃,ΔH = -30 kJ, to be at equilibrium ,the temperature should be
Options
(a) 750 K
(b) 1000 K
(c) 1250 K
(d) 500 K
Correct Answer:
750 K
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The solubility product of a sparingly soluble salt AB at room temperature
- The reduction of benzoyl chloride with H₂/Pd BaSO₄ gives
- MnO₃ in an acidic medium dissociates into
- As the nuclear charge increases from neon to calcium the orbital energy
- Which one of the following statements about halogens is correct
Topics: Thermodynamics
(179)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The solubility product of a sparingly soluble salt AB at room temperature
- The reduction of benzoyl chloride with H₂/Pd BaSO₄ gives
- MnO₃ in an acidic medium dissociates into
- As the nuclear charge increases from neon to calcium the orbital energy
- Which one of the following statements about halogens is correct
Topics: Thermodynamics (179)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply