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In a closed insulated container a liquid is stirred with a paddle to increase the temperature which of the following is true
Options
(a) ΔE = w ≠ 0, q = 0
(b) ΔE = w = q ≠ 0
(c) ΔE = 0, w = q ≠ 0
(d) w = 0, ΔE = q ≠ 0
Correct Answer:
ΔE = w ≠ 0, q = 0
Explanation:
The mathematical form of first law of thermodynamics : q = ΔE + W, Since the system is closed and insulated, q = 0, Paddle work is done on system. Therefore W ≠ 0. Temperature and hence internal energy of the system increases. Therefore ΔE ≠ 0.
Related Questions: - which of the following oxy acids of phosphorus is a reducing agent and monobasic
- Vanadium (III) oxide is a strong
- If 30 mL of H₂ and 20 mL of O₂ reacts to form water. what is left at the end
- Which of the following has a higher rate of reaction with water
- The four bonds in methane are directed in space with an angle of
Topics: Thermodynamics
(179)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- which of the following oxy acids of phosphorus is a reducing agent and monobasic
- Vanadium (III) oxide is a strong
- If 30 mL of H₂ and 20 mL of O₂ reacts to form water. what is left at the end
- Which of the following has a higher rate of reaction with water
- The four bonds in methane are directed in space with an angle of
Topics: Thermodynamics (179)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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