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In a closed insulated container a liquid is stirred with a paddle to increase the temperature which of the following is true
Options
(a) ΔE = w ≠ 0, q = 0
(b) ΔE = w = q ≠ 0
(c) ΔE = 0, w = q ≠ 0
(d) w = 0, ΔE = q ≠ 0
Correct Answer:
ΔE = w ≠ 0, q = 0
Explanation:
The mathematical form of first law of thermodynamics : q = ΔE + W, Since the system is closed and insulated, q = 0, Paddle work is done on system. Therefore W ≠ 0. Temperature and hence internal energy of the system increases. Therefore ΔE ≠ 0.
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Topics: Thermodynamics
(179)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Hardest compound of boron is
- dsp² hybridisation is found in
- In the reaction of H₂O₂ with acidified KMnO₄
- The number of unpaired electron in Mn²⁺ is
- 20.0 g of a magnesium carbonate sample decomposes on heating to give carbon dioxide
Topics: Thermodynamics (179)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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