A spherical liquid drop of radius R is divided into 8 equal droplets. If the surface

⇦

⇨

A spherical liquid drop of radius R is divided into 8 equal droplets. If the surface tension is T, then work done in the process will be

Options

(a) 2πR²T
(b) 3πR²T
(c) 4πR²T
(d) 2πRT²

Correct Answer:

4πR²T

Explanation:

Given: Surface tension = T
Radius of liquid drop = R
Let r be the radius of each small droplet
.·. Volume of big drop = volume of small droplets
(4/3) πR³ = 8 x (4/3) πr²
or R = 2r or r = R/2 ——(i)
Surface area of big drop = 4πR²
Surface are of 8 small droplets = 8 x 4πr²
8 x 4π x (R/2)² = 2(4πR²)
Increase in surface area = 2(4πR²) – 4πR² = 4πR²
Work done = T x increase in surface area
= T x 4πR² = 4πR²T.

Related Questions:

1. A gramophone record is revolving with an angular velocity ?. A coin is placed at
2. Water flows through a pipe. The area of cross-section at one place A₁=10 cm²,
3. When 1 kg of ice at 0⁰C melts to water at 0⁰C, the resulting change in its entropy
4. A 50Hz AC signal is applied in a circuit of inductance of (1/π)H and resistance 2100Ω
5. In a diffraction pattern due to a singleslit of width a, the first minimum is observed

Topics: Properties of Bulk Matter (130)
Subject: Physics (2479)

---

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

---

Share this page with your friends