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Radius of a soap bubble is increased from R to 2R. Work done in this process in terms of surface tension S is
Options
(a) 24 πR²S
(b) 48 πR²S
(c) 12 πR²S
(d) 36 πR²S
Correct Answer:
24 πR²S
Explanation:
Work done = 2 x S x Change in surface area
W = 2 x S x 4π (R₂² – R₁²)
Given: R₂ = 2R, R₁ = R = 8S π (4R² – R²) = 24 πR²S.
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Topics: Properties of Bulk Matter
(130)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A body is thrown upward from ground covers equal distances
- A 0.01 H inductor and √3 πΩ resistance are connected in series
- The internal energy change in a system that has absorbed 2 kcals of heat
- Electrons used in an electron microscope are accelerated by a voltage of 25 kV
- Minority carriers in a p-type semiconductor are
Topics: Properties of Bulk Matter (130)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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