| ⇦ | 
| ⇨ |
The area of cross-section of a steel wire (Y=2.0×10¹¹ N/m²) is 0.1 cm². The force required to double its length will be
Options
(a) 2×10¹² N
(b) 2×10¹¹ N
(c) 2×10¹⁰ N
(d) 2×10⁶ N
Correct Answer:
2×10⁶ N
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - When radiation is incident on a photoelectron emitter,
- The identical cells connected in series are needed to heat a wire of length one meter
- A 0.5 kg ball moving with a speed of 12 m/s strikes a hard wall at an angle
- Sodium and copper have work function 2.3 eV and 4.5 eV respectively
- A cockroach is moving with a velocity v in anticlockwise direction on the rim
Topics: Properties of Bulk Matter
(130)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- When radiation is incident on a photoelectron emitter,
- The identical cells connected in series are needed to heat a wire of length one meter
- A 0.5 kg ball moving with a speed of 12 m/s strikes a hard wall at an angle
- Sodium and copper have work function 2.3 eV and 4.5 eV respectively
- A cockroach is moving with a velocity v in anticlockwise direction on the rim
Topics: Properties of Bulk Matter (130)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply