⇦ | ![]() | ⇨ |
The area of cross-section of a steel wire (Y=2.0×10¹¹ N/m²) is 0.1 cm². The force required to double its length will be
Options
(a) 2×10¹² N
(b) 2×10¹¹ N
(c) 2×10¹⁰ N
(d) 2×10⁶ N
Correct Answer:
2×10⁶ N
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Three capacitors each of capacitance C and of breakdown voltage V are joined in series
- A wire of length 2 m is made from 10 cm³ of copper. A force F is applied so that
- A particle of masses m is thrown upwards from the surface of the earth, with a velocity u
- A train of mass 2x 10⁵ kg has a constant speed of 20 m/s up a hill inclined
- Pure Si at 300 k has equal electrons (nₑ) and hole (nh) concentrations
Topics: Properties of Bulk Matter
(130)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Three capacitors each of capacitance C and of breakdown voltage V are joined in series
- A wire of length 2 m is made from 10 cm³ of copper. A force F is applied so that
- A particle of masses m is thrown upwards from the surface of the earth, with a velocity u
- A train of mass 2x 10⁵ kg has a constant speed of 20 m/s up a hill inclined
- Pure Si at 300 k has equal electrons (nₑ) and hole (nh) concentrations
Topics: Properties of Bulk Matter (130)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply