| ⇦ | 
| ⇨ |
Acetylene, on reacting with formaldehyde under high pressure, gives
Options
(a) propanol
(b) propyl alcohol
(c) allyl aldehyde
(d) butyndiol
Correct Answer:
butyndiol
Explanation:
HC ≡ CH + HCHO (Acetylene) → HC ≡ C – CH₂OH (Formaldehyde)
HC ≡ C – CH₂OH + H – C = O → HOCH₂C ≡ CCH₂OH ( But – 2- yn-1,4-diol)
Related Questions: - The solubility of BaSO₄, in water, is 2.33 ˣ 10⁻³ g/L.Its solubility product
- Which of the following is a representation of Gay-Lussac’s law
- Which one of the following species has plane triangular shape
- P₂O₅ is an anhydride of
- In the equation of state of an ideal gas PV = nRT, the value of the universal gas
Topics: Hydrocarbons
(84)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The solubility of BaSO₄, in water, is 2.33 ˣ 10⁻³ g/L.Its solubility product
- Which of the following is a representation of Gay-Lussac’s law
- Which one of the following species has plane triangular shape
- P₂O₅ is an anhydride of
- In the equation of state of an ideal gas PV = nRT, the value of the universal gas
Topics: Hydrocarbons (84)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
C2H2+2HCOH=OHCH2CCCH2OH