| ⇦ | 
| ⇨ |
The compound which contains all the four 1°,2°,3° and 4° carbon atoms is
Options
(a) 2,3-dimethylpentane
(b) 3-chloro-2,3-dimethylpentane
(c) 2,3,4-trimethylpentane
(d) 3,3-dimethylpentane
Correct Answer:
3-chloro-2,3-dimethylpentane
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The inert form of carbon is
- Correct order of first IP among following elements Be, B, C, N, O is
- In Duma’s method for estimation of nitrogen, 0.25g of an organic compound
- The strongest reducing agent among the following is
- ‘The addition of unsymmetrical reagents to unsymmetrical alkenes occurs in such
Topics: Hydrocarbons
(84)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The inert form of carbon is
- Correct order of first IP among following elements Be, B, C, N, O is
- In Duma’s method for estimation of nitrogen, 0.25g of an organic compound
- The strongest reducing agent among the following is
- ‘The addition of unsymmetrical reagents to unsymmetrical alkenes occurs in such
Topics: Hydrocarbons (84)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
The compound in option b is a 4 degree compound as it has 4 different atoms attached to its hydrogen’s position. The carbon at 2nd position is 3 degree while the carbon at 4th position is 2 degree.
Option B is correct coz this is only compound which contain all four 1°, 2°, 3°& 4° c-atom as if we make the structure of this compound we will see that at carbon at 2nd postion is 3°while the carbon at 3rd postion is of 4°..thats why option b is correct👍