| ⇦ | 
| ⇨ |
What is the pH of 0.01 M glycine solution? For glycine, Ka₁ = 4.5 ˣ 10⁻³ and Ka₂ =1.7 ˣ 10⁻¹⁰ at 298 K
Options
(a) 3
(b) 10
(c) 6.1
(d) 7.2
Correct Answer:
6.1
Explanation:
K = Kₐ₁ x Kₐ₂ = 4.5 x 10⁻³ * 1.7 x 10⁻¹⁰,
7.65 x 10⁻¹³,
[H⁺] = √KC = √7.65 x 10⁻¹³ x 0.01 ,
= √7.65 x 10⁻¹⁵
= 0.87 x 10⁻⁷. pH = -log 0.87 x 10⁻⁷
= 7 – 0.93 = 6.07.
Related Questions: - Which one of the following elements has the maximum electron affinity?
- Of the following, which change will shift the reaction towards the product
- Anomalous behaviour of nitrogen is due to
- In the case of alkali metals, the covalent character decreases in the order
- M⁺³ ion loses 3e⁻. Its oxidation number will be
Topics: Equilibrium
(104)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Which one of the following elements has the maximum electron affinity?
- Of the following, which change will shift the reaction towards the product
- Anomalous behaviour of nitrogen is due to
- In the case of alkali metals, the covalent character decreases in the order
- M⁺³ ion loses 3e⁻. Its oxidation number will be
Topics: Equilibrium (104)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply