⇦ | ![]() | ⇨ |
Energy of all molecules of a monoatomic gas having a volume V and pressure P is (3PV/2). The total translational kinetic energy of all molecules of a diatomic gas having the same volume and pressure is
Options
(a) PV/2
(b) 3PV/2
(c) 5PV/2
(d) 3PV
Correct Answer:
3PV/2
Explanation:
Translational kinetic energy depends upon translational degree of freedom. These degree are three for monoatomic as well as diatomic gases. Hence under same pressure, equal volumes of monoatomic and diatomic molecules have same translational kinetic energy i.e. (3 / 2) PV.
Related Questions:
- A radiation of energy ‘E’ falls normally on a perfectly reflecting surface
- If sound wave travel from air to water, which of the following remains unchanged?
- The angle of a prism is A. One of its refracting surfaces is silvered
- Two bodies A and B having temperature 327° C and 427° C are radiating heat
- Dimensions formula for surface tension is
Topics: Behavior of Perfect Gas and Kinetic Theory
(34)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply