| ⇦ | 
| ⇨ |
Energy of all molecules of a monoatomic gas having a volume V and pressure P is (3PV/2). The total translational kinetic energy of all molecules of a diatomic gas having the same volume and pressure is
Options
(a) PV/2
(b) 3PV/2
(c) 5PV/2
(d) 3PV
Correct Answer:
3PV/2
Explanation:
Translational kinetic energy depends upon translational degree of freedom. These degree are three for monoatomic as well as diatomic gases. Hence under same pressure, equal volumes of monoatomic and diatomic molecules have same translational kinetic energy i.e. (3 / 2) PV.
Related Questions: - In a nuclear reactor, the number of U²³⁵ nuclei undergoing fissions per second
- A ball is dropped from a high rise platform at t = 0 starting from rest
- An alpha nucleus of energy 1/2 mv² bombards a heavy nuclear target of charge Ze
- A stone thrown into still water, creates a circular wave pattern moving radially
- For a simple pendulum performing simple harmonic motion, the time period
Topics: Behavior of Perfect Gas and Kinetic Theory
(34)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In a nuclear reactor, the number of U²³⁵ nuclei undergoing fissions per second
- A ball is dropped from a high rise platform at t = 0 starting from rest
- An alpha nucleus of energy 1/2 mv² bombards a heavy nuclear target of charge Ze
- A stone thrown into still water, creates a circular wave pattern moving radially
- For a simple pendulum performing simple harmonic motion, the time period
Topics: Behavior of Perfect Gas and Kinetic Theory (34)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply