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Energy of all molecules of a monoatomic gas having a volume V and pressure P is (3PV/2). The total translational kinetic energy of all molecules of a diatomic gas having the same volume and pressure is
Options
(a) PV/2
(b) 3PV/2
(c) 5PV/2
(d) 3PV
Correct Answer:
3PV/2
Explanation:
Translational kinetic energy depends upon translational degree of freedom. These degree are three for monoatomic as well as diatomic gases. Hence under same pressure, equal volumes of monoatomic and diatomic molecules have same translational kinetic energy i.e. (3 / 2) PV.
Related Questions: - Which one of the following statements is not correct in case of a semiconductor?
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Topics: Behavior of Perfect Gas and Kinetic Theory
(34)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Which one of the following statements is not correct in case of a semiconductor?
- A thin film of soap solution (n=1.4) lies on the top of a glass plate (n=1.5).
- If in a nuclear fusion process, the masses of the fusing nuclei be m₁ and m₂
- A ballon rises from rest with a constant acceleration g/8. A stone is released
- Four identical rods are joined to from a square. If the temperature difference
Topics: Behavior of Perfect Gas and Kinetic Theory (34)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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