⇦ | ⇨ |
A solid sphere of mass M, radius R and having moment of inertia about an axis passing through the centre of mass as I, is recast into a disc of thickness t, whose moment of inertia about an axis passing through its edge and perpendicular to its plane remains I. Then, radius of the disc will be
Options
(a) 2R/√15
(b) R√2/15
(c) 4R/√15
(d) R/4
Correct Answer:
2R/√15
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Under constant pressure, graph between P and 1/V is a
- An iron rod of volume 10⁻⁴ m³ and relative permeability 1000 is placed inside a long
- The electric field at a distance 3R / 2 from the centre of a charged conducting
- Find the maximum velocity with which a train can be moved on a circular track
- A rod of 10 cm length is moving perpendicular to uniform magntic field of intensity
Topics: Motion of system of Particles and Rigid Body
(73)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Under constant pressure, graph between P and 1/V is a
- An iron rod of volume 10⁻⁴ m³ and relative permeability 1000 is placed inside a long
- The electric field at a distance 3R / 2 from the centre of a charged conducting
- Find the maximum velocity with which a train can be moved on a circular track
- A rod of 10 cm length is moving perpendicular to uniform magntic field of intensity
Topics: Motion of system of Particles and Rigid Body (73)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply