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Four indentical thin rods each of mass M and length l, form a square frame. Momentum of inertia of this frame about an axis through the centre of the square and perpendicular to its plane is:
Options
(a) 2/3 MI²
(b) 13/3 MI²
(c) 1/3 MI²
(d) 4/3 MI²
Correct Answer:
4/3 MI²
Explanation:
Moment of inertia of oa thin rod of length l about an axis passing through centre and perpendicular to the rod = 1/12 MI².
Thus, moment of inertia of the frame.
MI² / 12 + MI² / 4 = 4 MI² / 12 = MI² / 3
Total M.I. = 4/3 MI²
Related Questions: - The valence band and the conductance band of a solid overlap at low temperature
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Topics: Motion of system of Particles and Rigid Body
(73)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The valence band and the conductance band of a solid overlap at low temperature
- The maximum and minimum magnitudes of the resultant of two vectors
- The friction of the air causes a vertical retardation equal to 10%
- A particle doing SHM has amplitude=4 cm and time period = 12 sec. The ratio between times
- If a spring of spring constant k stretched by a length x under tension T, the energy
Topics: Motion of system of Particles and Rigid Body (73)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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