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Four indentical thin rods each of mass M and length l, form a square frame. Momentum of inertia of this frame about an axis through the centre of the square and perpendicular to its plane is:
Options
(a) 2/3 MI²
(b) 13/3 MI²
(c) 1/3 MI²
(d) 4/3 MI²
Correct Answer:
4/3 MI²
Explanation:
Moment of inertia of oa thin rod of length l about an axis passing through centre and perpendicular to the rod = 1/12 MI².
Thus, moment of inertia of the frame.
MI² / 12 + MI² / 4 = 4 MI² / 12 = MI² / 3
Total M.I. = 4/3 MI²
Related Questions: - A wire of resistance 4 ohm is stretched to twice its original length.
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Topics: Motion of system of Particles and Rigid Body
(73)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A wire of resistance 4 ohm is stretched to twice its original length.
- An electric dipole of length 1 cm is placed with the axis making an angle of 30⁰
- The excitation potential of hydrogen atom in the first excited state is
- A particle is moving such that its position coordinates (x,y) are (2 m,3 m) at time
- One-fourth length of a spring of force constant K is cut away. The force constant
Topics: Motion of system of Particles and Rigid Body (73)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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