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Charge q is uniformly spread on a thin ring of radius R. The ring rotates about its axis with a uniform frequency f Hz. The magnitude of magnetic induction at the centre of the ring is
Options
(a) µ₀q f / 2 R
(b) µ₀q / 2 f R
(c) µ₀q / 2π f R
(d) µ₀q f / 2π R
Correct Answer:
µ₀q f / 2 R
Explanation:
When the ring rotates f Hz, the current flowing in the ring is i = q/T = qf
Magnetic field at the centre of the ring is
B = µ₀I / 2 R = µ₀q f / 2 R
Related Questions: - If the minimum energy of photons needed to produce photoelectrons is 3 eV,
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Topics: Magnetic Effects of Current and Magnetism
(167)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If the minimum energy of photons needed to produce photoelectrons is 3 eV,
- A compass needle which is allowed to move in a horizontal plane
- Pressure gradient has the same dimensions as that of
- If a small sphere is let fall vertically in a large quantity of still liquid of density
- A condenser of 250 μF is connected in parallel to a coil of inductance of 0.16 mH
Topics: Magnetic Effects of Current and Magnetism (167)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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