| ⇦ |
| ⇨ |
Aniline is treated with a mixture of sodium nitrite and hypophosphorus acid, the product formed is
Options
(a) aniline diazonium hypophosphate
(b) benzene
(c) anilinium hypophosphite
(d) aniline diazonium hypophosphite
Correct Answer:
benzene
Explanation:
H₃PO₂ serves both as an acid as well as a reducing agent. The diazonium salt initially formed is reduced to give benzene. C₆H₅NH₂ → C₆H₅N₂⁺ HPO₂⁻ → C₆H₆ + N₂ .
Related Questions: - In which of the following compounds manganese has oxidation number equal
- Dalton predicted
- A gas mixture contains 50% He and 50% Methane by volume. What is the percent
- Which of the following materials is used in high temperature thermometers
- What is the number of mols of hydrogen atoms in 3.2g of methane
Topics: Organic compounds containing Nitrogen
(87)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In which of the following compounds manganese has oxidation number equal
- Dalton predicted
- A gas mixture contains 50% He and 50% Methane by volume. What is the percent
- Which of the following materials is used in high temperature thermometers
- What is the number of mols of hydrogen atoms in 3.2g of methane
Topics: Organic compounds containing Nitrogen (87)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply