| ⇦ | 
| ⇨ |
Aniline is treated with a mixture of sodium nitrite and hypophosphorus acid, the product formed is
Options
(a) aniline diazonium hypophosphate
(b) benzene
(c) anilinium hypophosphite
(d) aniline diazonium hypophosphite
Correct Answer:
benzene
Explanation:
H₃PO₂ serves both as an acid as well as a reducing agent. The diazonium salt initially formed is reduced to give benzene. C₆H₅NH₂ → C₆H₅N₂⁺ HPO₂⁻ → C₆H₆ + N₂ .
Related Questions: - How many coulombs of electricity are required for the reduction of 1 mol
- For the cell reactionCu²⁺ (C₁.aq) + Zn(s) = Zn²⁺(C₂.aq ) + Cu(s)
- Proteins gives purple colour when tested with
- Diethyl ether is isomeric with
- The heat of neutralization of a strong base and a strong acid is 57 kJ.
Topics: Organic compounds containing Nitrogen
(87)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- How many coulombs of electricity are required for the reduction of 1 mol
- For the cell reactionCu²⁺ (C₁.aq) + Zn(s) = Zn²⁺(C₂.aq ) + Cu(s)
- Proteins gives purple colour when tested with
- Diethyl ether is isomeric with
- The heat of neutralization of a strong base and a strong acid is 57 kJ.
Topics: Organic compounds containing Nitrogen (87)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply