| ⇦ | 
| ⇨ |
The case of adsorption of the hydrated alkali metal ions on an ion-exchange resins follows the order:
Options
(a) Li⁺ < K⁺ < Na⁺ < Rb⁺
(b) Rb⁺ < K⁺ < Na⁺ < Li⁺
(c) K⁺ < Na⁺ < Rb⁺ < Li⁺
(d) Na⁺ < Li⁺ < K⁺ < Rb⁺
Correct Answer:
Rb⁺ < K⁺ < Na⁺ < Li⁺
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - At S.T.P the density of CCl₄ vapours in g/L will be nearest to
- A 2.5 mol sample of N₂H₄ loses 25 mol of electrons in being converted
- ortho and para hydrogen differ in the
- n-Butane and isobutane are
- Which of the following is not soluble in NaOH
Topics: S and Some P Block Elements
(157)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- At S.T.P the density of CCl₄ vapours in g/L will be nearest to
- A 2.5 mol sample of N₂H₄ loses 25 mol of electrons in being converted
- ortho and para hydrogen differ in the
- n-Butane and isobutane are
- Which of the following is not soluble in NaOH
Topics: S and Some P Block Elements (157)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply