| ⇦ | 
| ⇨ |
The radius of curvature of a concave mirror is 24 cm and the imager is magnified by 1.5 times. The object distance is
Options
(a) 20 cm
(b) 8 cm
(c) 16 cm
(d) 24 cm
Correct Answer:
20 cm
Explanation:
R = -24 cm, f = -12 cm, m = 1.5
(1 / v) + (1 / u) = 1 / f
.·. u = 20 cm.
Related Questions: - For a wave propagating in a medium, identify the property that is independent
- The horizontal range and maximum height of a projectile are equal.The angle of projection
- A bullet comes out of the barrel of gun of length 2m with a speed of 800 m/s
- A moving neutron collides with a stationary α-particle.The fraction of the kinetic energy
- RMS velocity of gas is proportional to
Topics: Ray Optics
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- For a wave propagating in a medium, identify the property that is independent
- The horizontal range and maximum height of a projectile are equal.The angle of projection
- A bullet comes out of the barrel of gun of length 2m with a speed of 800 m/s
- A moving neutron collides with a stationary α-particle.The fraction of the kinetic energy
- RMS velocity of gas is proportional to
Topics: Ray Optics (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
given that
R=24 cm
f=R/2=24/2=12 cm
and m= -v/u = -3/2……..(1)
v=3/2 u ………….(2)
from mirror equation,
1/v+1/u=1/f…………….(3)
putting the value of f and v in equation (3) we get,
2/3u+1/u=1/12
3u=60
u=20 cm